. such that ar (
) = 4 ar (
). If BC =12 cm, then QR =
Given ar (ΔABC) ~ ar (PQR) such that ar (ΔABC) = 4 ar (ΔPQR) and BC = 12 cm
We know that ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.
∴ QR = 6 cm