If
such that DE = 3 cm, EF = 2 cm, DF = 2.5 cm, BC = 4 cm, then perimeter of
is
Given that ΔABC and ΔDEF are similar triangles such that AB = 3 cm, DE = 3 cm, DF = 2.5 cm and EF = 2 cm.
We know that two triangles are similar if their corresponding sides are proportional.
First consider,
⇒ AB = 6 cm … (1)
Now,
⇒ CA = 5 cm … (2)
Then, perimeter of ΔABC = AB + BC + CA = 6 + 4 + 5
∴ Perimeter of ΔABC = 15 cm