The track shown in figure (9-E16) is frictionless. The block B of mass 2m is lying at rest and the block A of mass m is pushed along the track with some speed. The collision between A and B is perfectly elastic. With what velocity should the block A be started to get the sleeping man awakened?
Given that the block B has mass 2m and the block A has mass m.
Let the velocity of A is uat which it should started,
Let the final velocity when reaching at B becomes v1,
Since, by work energy principle
________________ (1)
When the block B reached at the upper man’s head, the velocity of B is just zero.
For block B, applying work energy principle
Therefore,
Therefore, before collision the initial velocity of block A is v1 and initial velocity of block B is 0.
After collision the final velocity of block A is v (say) and final velocity of block B is
Since it is an elastic collision the momentum and kinetic energy should be conserved.
Therefore,
___________ (1b)
By law of conservation of energy
________________ (2)
Dividing equation (1) by (2)
_____________ (3)
Adding (1b) and (3)
But
So With velocity should the block A be started to get the sleeping man awakened.