The track shown in figure (9-E16) is frictionless. The block B of mass 2m is lying at rest and the block A of mass m is pushed along the track with some speed. The collision between A and B is perfectly elastic. With what velocity should the block A be started to get the sleeping man awakened?



Given that the block B has mass 2m and the block A has mass m.


Let the velocity of A is uat which it should started,


Let the final velocity when reaching at B becomes v1,


Since, by work energy principle




________________ (1)


When the block B reached at the upper man’s head, the velocity of B is just zero.


For block B, applying work energy principle


Therefore,




Therefore, before collision the initial velocity of block A is v1 and initial velocity of block B is 0.


After collision the final velocity of block A is v (say) and final velocity of block B is


Since it is an elastic collision the momentum and kinetic energy should be conserved.


Therefore,



___________ (1b)


By law of conservation of energy



________________ (2)


Dividing equation (1) by (2)



_____________ (3)


Adding (1b) and (3)




But




So With velocity should the block A be started to get the sleeping man awakened.


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