What is the IUPAC name of the given compound?
2 –hydroxy 1,4-dinirobenzene
Here we are numbering anticlock wise starting with the carbon having –NO2 on right giving it 1, followed by carbon with –OH group which gets number 2 and the other carbon with –NO2 gets the number 4. If we name in this order alone the lowest possible numbering is obtained. As there are two different substituents –NO2 gets priority over –OH hence –OH named as hydroxy. Since there are 2 nitro groups we use a prefix di.