In the following ions: Mn 3+ , V 3+ , Cr 3+ , Ti 4+ (Atomic no.: Mn=25, V=23, Cr=24, Ti=22) (a) Which ion is most stable in an aqueous solution? (b) Which ion is the strongest oxidizing agent? (c) Which ion is colorless? (d) Which ion has the highest number of unpaired electrons?

Question

Philoid · Accepted Answer

(a) Out of all these ions, the most stable ion in an aqueous solution is Cr³⁺ because it has half filled t_2g orbital which accounts for its extra stability.

Electronic configuration of Cr³⁺: 4s⁰ 3d³ or t_2g³ e_g⁰

(b) Mn³⁺ is the strongest oxidizing agent because an oxidizing agent itself gets reduced, so Mn³⁺ will be reduced to Mn²⁺ and will attain stable half filled d⁵ configuration. That’s why Mn³⁺ will be the strongest oxidizing agent.

(c) Ti⁴⁺ will be colorless because it does not have any electron in the d orbital for d-d transition which is responsible for giving color to a solution. Electronic configuration of Ti⁴⁺is 4s⁰ 3d⁰.

(d) Mn³⁺ ion has the highest number of unpaired electrons. It has 4 unpaired electrons in the d orbital. Electronic configuration of Mn³⁺is 4s⁰ 3d⁴.

In the following ions: Mn3+, V3+, Cr3+, Ti4+ (Atomic no.: Mn=25, V=23, Cr=24, Ti=22)(a) Which ion is most stable in an aqueous solution?(b) Which ion is the strongest oxidizing agent?(c) Which ion is colorless?(d) Which ion has the highest number of unpaired electrons?

In the following ions: Mn³⁺, V³⁺, Cr³⁺, Ti⁴⁺ (Atomic no.: Mn=25, V=23, Cr=24, Ti=22)
(a) Which ion is most stable in an aqueous solution?

(b) Which ion is the strongest oxidizing agent?

(c) Which ion is colorless?

(d) Which ion has the highest number of unpaired electrons?