A capacitor of 4 μ F is connected in a circuit as shown. The internal resistance of the battery is 0.5 Ω. The amount of charge on the capacitor plates will be




In steady state, there will be no current in the capacitor branch


Net resistance of the circuit


Current drawn from the cell


Potential drop across two parallel branches



So, charge on the capacitor plates



Under steady state capacitor becomes open circuited therefore whatever Vc (capacitor voltage) you need it is nearly equal to V1


correct answer is 8μC

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