A topper wire of cross-sectional area 0.01 cm is under tension of 20 N. Find the decrease in the cross-sectional area Young modulus of copper = 1.1 × 10¹¹ N m^-2 and Poisson ratio = 0.32.

Question

A topper wire of cross-sectional area 0.01 cm is under tension of 20 N. Find the decrease in the cross-sectional area Young modulus of copper = 1.1 × 10 11 N m -2 and Poisson ratio = 0.32.

Philoid · Accepted Answer

1.164 × 10^-6 cm²

Given, cross-sectional area,

Tension in the wire,

Young modulus of the wire,

We know, stress,

And strain is given by ,

Young’s modulus then becomes,

therefore, longitudinal strain becomes,

Let the circular cross-section be of diameter

Given, Poisson’s ratio

hence, lateral strain

We know, area is given by

A topper wire of cross-sectional area 0.01 cm is under tension of 20 N. Find the decrease in the cross-sectional area Young modulus of copper = 1.1 × 1011 N m-2 and Poisson ratio = 0.32.

A topper wire of cross-sectional area 0.01 cm is under tension of 20 N. Find the decrease in the cross-sectional area Young modulus of copper = 1.1 × 10¹¹ N m^-2 and Poisson ratio = 0.32.