Consider the situation of the previous problem. If the mirror reflects only 64% of the light energy falling on it, what will be the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen?

Let the original intensity of light be and that after reflection be .

Given,

We know that intensities are directly proportional to the square of the amplitude. Let the initial amplitude be and that after reflection be .

Here, k is some constant.

Therefore, and .

Now, the maximum amplitude is

And minimum amplitude is

Therefore, ratio of maximum intensity to minimum is