In a Young’s double slit experiment λ = 500 nm, d = 1.0 mm and D = 1.0 m. Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.
Given, separation between the slits ![]()
The distance between the screen and the slit, ![]()
Wavelength of light,
.
Let the maximum intensity be
and the intensity at y be
.
Given,
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therefore, path difference, ![]()
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