The rod AC of a TV disc antenna is fixed at right angles to the wall AB and a rod CD is supporting the disc as shown in fig. 4. If AC = 1.5 m long and CD = 3 m, find (i) tan θ (ii) sec θ + cosec θ.

We have,

⇒ sin θ = 1.5/3 = 1/2

⇒ θ = 30°

(i)

(ii)

1
1

Question

The rod AC of a TV disc antenna is fixed at right angles to the wall AB and a rod CD is supporting the disc as shown in fig. 4. If AC = 1.5 m long and CD = 3 m, find (i) tan θ (ii) sec θ + cosec θ.

Philoid · Accepted Answer

We have,

⇒ sin θ = 1.5/3 = 1/2

⇒ θ = 30°

(i)

(ii)