If x = -1/2 is a zero of the polynomial p (x) = 8xax+ 2, find the value of a.


We have,


p (x) = 8xax+ 2


 


Put x = -1/2


 


p (-1/2) = 8 (-1/2)2 – a (-1/2)2 – (-1/2) + 2


 


= 8 * – a * + + 2


 


= -1 - + + 2


 


= -


 


Given that,


 


x = -1/2 is a root of p (x)


 


p (-1/2) = 0


 


Therefore,


 


- = 0


 


=


 


2a = 12


 


a = 12/2 = 6


 

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