In each of the following, using the remainder theorem, find the remainder when f(x) is divided by g(x):
f(x) = 3x4+2x3
, g(x) = x+![]()
We have,
f(x) = 3x4+2x3
and g(x) = x+![]()
Therefore, by remainder theorem when f (x) is divided by g (x) = x – (-
), the remainder is equal to f (
)
Now, f(x) = 3x4+2x3![]()
f (
) = 3 (
)4 + 2 (
)3 – (
) -
+ ![]()
= 3 *
+ 2 *
-
-
+ ![]()
=
-
-
+
+ ![]()
=
= ![]()
= 0
Hence, required remainder is 0.