If the polynomials 2x3+ax2+3x-5 and x3+x2-4x+a leave the same remainder when divided by x-2, find the value of a.
Let, p (x) = 2x3+ax2+3x-5 and q (x) = x3+x2-4x+a be the given polynomials.
The remainders when p (x) and q (x) are divided by (x – 2) and p (2) and q (2) respectively.
By the given condition, we have:
p (2) = q (2)
2 (2)3 + a (2)2 + 3 (2) – 5 = (2)3 + (2)2 – 4 (2) + a
16 + 4a + 6 – 5 = 8 + 4 – 8 + a
3a + 13 = 0
3a = - 13
a =