In Fig 8.107, AB ||CD ||EF and GH ||KL. Find ∠HKL.
Produce LK to meet GF at N
Now,
∠CHG = ∠HGN = 60o(Alternate angle)
∠HGN = ∠KNF = 60o(Corresponding angles)
Therefore,
∠KNG = 120o
∠GNK = ∠AKL = 120o(Corresponding angle)
∠AKH = ∠KHD = 25o(Alternate angles)
Therefore,
∠HKL = ∠AKH + ∠AKL
= 25o + 120o
= 145o