In Fig 8.120, arms BA and BC of ABC are respectively parallel to arms ED and EF of DEF. Prove that ABC = DEF.


Given that,

AB DE and EC EF


To prove: ABC = DEF


Construction: Produce BC to X such that it intersects DE at M


Proof: Since, AB DE and BX is the transversal


Therefore,


ABC = DMX (Corresponding angles) (i)


Also,


BX EF and DE is transversal


Therefore,


DMX = DEF (Corresponding angles) (ii)


From (i) and (ii), we get


ABC = DEF


Hence, proved


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