If two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio 2:3, then the measure of the larger angle is

Let,

l and m be two parallel lines and transversal p cuts them

∠1: ∠2 = 2: 3 (Interior angles on same side)

Let,

∠1 = 2k

∠2 = 3k

∠1 + ∠2 = 180^o (Interior angle)

2k + 3k = 180^o

k = 36^o

So, ∠1 = 2k = 72^o

∠2 = 3k = 108^o

Hence, larger angle is 108^o