AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of ∠FEB. If ∠LEB =35°, then ∠CFQ will be

Question

AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of &#x2220; FEB. If &#x2220; LEB =35&#xB0;, then &#x2220; CFQ will be

Philoid · Accepted Answer

Given that,

AB ‖ CD and PQ cuts them

EL is bisector of ∠FEB

∠LEB = ∠FEL = 35^o

∠FEB = ∠LEB + ∠FEL

= 35^o + 35^o

= 70^o

∠FEB = ∠EFC = 70^o (Alternate angles)

∠EFC + ∠CFQ = 180^o (Linear pair)

70^o + ∠CFQ = 180^o

∠CFQ = 110^o

AB and CD are two parallel lines. PQ cuts AB and CD at E and F respectively. EL is the bisector of ∠FEB. If ∠LEB =35°, then ∠CFQ will be