In Fig. 8.140, if lines l and m are parallel lines, then x =
Given that,
l ‖ m
Let, l ‖ m and transversal cuts them and
∠1 = 70o
∠3 = 20o
∠4 = 30o
∠1 + ∠2 = 180o (Interior angle)
∠2 = 110o (i)
∠2 = ∠5 (Vertically opposite angle)
∠5 = 110o (ii)
∠5 + ∠3 + ∠4 = 180o (Sum of angles of a triangle is 180o)
110o + x + 30o = 180o
x = 40o