In Fig. 8.141, if l || m, then x =
Given that,
l ‖ m and n cuts them
Let,
∠1 = 65o
∠2 = x
∠3 = 40o
∠1 = ∠4 = 65o (Alternate angle) (i)
∠3 + ∠4 + ∠5 = 180o (Angle sum property)
40o + 65o + ∠5 = 180o
∠5 = 75o
Now,
∠2 + ∠5 = 180o (Linear pair)
x + 75o = 180o
x = 105o