In Δ ABC, if bisectors of ∠ABC and ∠ACB intersect at O angle of 120°, then find the measure of ∠A.
In
∠BOC + ∠OBC + ∠OCB = 180o
120o + ∠B +
∠C = 180o
(∠B + ∠C) = 60o
∠B + ∠C = 120o (i)
In
∠A + ∠B + ∠C = 180o
∠A + 120o = 180o [From (i)]
∠A = 60o