The base BC of triangle ABC is produced both ways and the measure of exterior angles formed are 94° and 126°. Then, ∠BAC=
Given,
∠ABD = 94o and
∠ACE = 126o
∠ABD + ∠ABC = 180o (Linear pair)
∠ABC = 86o (i)
∠ACE + ∠ACB = 180o (Linear pair)
∠ACB = 54o (ii)
In
∠ABC + ∠ACB + ∠BAC = 180o
86o + 54o + ∠BAC = 180o
∠BAC = 40o