If the squared difference of the zeros of the quadratic polynomial 
is equal to 144, find the value of p.
Let one root of the given quadratic polynomial is 
Other root of the given quadratic polynomial is β
Sum of the roots = 
= 
= 
= -p
Product of the roots = 
= 
= 45
According to the question: squared difference of the zeros = 144
= 144
2 - 4× 45 = 144
⇒ 
2 = 324
⇒ 
= ±18
12