ABC is a triangle in which = 90°, , BC = 12 cm and AC = 5 cm. Find the ratio of the areas of .

In Δ ANC and Δ ABC

<C = <C (Common)

<ANC = <BAC (Each 90°)

Then, Δ ANC ~ Δ ABC (By AA similarity)

By area of similarity triangle theorem.

Area of ΔABC/Area of ΔPQR = AC² /BC²

Or, 5²/12²

Or, 25/144