In , P divides the side AB such that AP : PB = 1 : 2. Q is a point in AC such that
. Find the ratio of the areas of
and trapezium BPQC.
We know
PQ∥BC
1= AP
2 PB
In
∠A=∠A [Common]
∠APQ=∠B [Corresponding angle]
ABC
APQ
Area() =AP2
Area () AB2
ar ()___________ = 12/32
ar()+ar(
)
9ar()= ar(
)+ar(
)
9ar()- ar(
)=ar(
)
8ar()=ar(
)
ar() =
ar()