In , P divides the side AB such that AP : PB = 1 : 2. Q is a point in AC such that . Find the ratio of the areas of and trapezium BPQC.
We know
PQ∥BC
1= AP
2 PB
In
∠A=∠A [Common]
∠APQ=∠B [Corresponding angle]
ABCAPQ
Area() =AP2
Area () AB2
ar ()___________ = 12/32
ar()+ar()
9ar()= ar()+ar()
9ar()- ar()=ar()
8ar()=ar()
ar() =
ar()