In , PQ is a line segment intersecting AB at P and AC at Q such that
and PQ divides
into two parts equal in area. Find
.
We know
PQ∥BC
Area () =Area (
)
Area () =Area (
)- Area (
)
2Area ()= Area (
) ………(i)
In
∠A=∠A [Common]
∠APQ=∠B [Corresponding angle]
ABC
APQ
Area() =AP2
Area () AB2
Area() =AP2
Area () AB2 [By using (I)]
1= AP2
2 AB2
=AP/AB
=
=
-
=1-BP/AB
BP/AB=1-
BP/AB=