In a
, AB = BC = CA = 2 a and
. Prove that
(i)
(ii) Area (
) = ![]()

(i) In
ABD and
ACD
ADB=
ADC=90![]()
AB=AC (given)
AD=AD (common)
ADB
ACD
BD=CD=a (By c.p.c.t)
In
ADB
AD2+BD2=AB2
AD2+a2=(2a)2
AD2=4a2-a2
AD2=3a2
AD=a![]()
(ii) Area of
ABC=1/2xBCxAD
= 1/2x2axa![]()
=
3a2