Each side of a rhombus is 10 cm. If one of its diagonals is 16 cm find the length of the other diagonal.
We have,
ABCD is a rhombus with side 10 cm and diagonal BD=16 CM
We know that rhombus of diagonal bisects each other at 90
BO=OD=8cm
In AOB
AB2=AO2+BO2
102= AO2 +82
100= AO2+64
AO2=100-64
AO2=36
AO=
AO=6 cm
∴ AC=AO+OC
AC=6+6
AC=12 cm