Solve the following systems of equations:

Question

Philoid · Accepted Answer

Multiplying eq1 by 9 and eq2 by 2 and adding

⇒ 120/(x + y) = 32

⇒ x + y = 15/4 ---- (1)

Multiplying eq1 by 3 and eq2 by 2 and subtracting

⇒ 24/(x – y) = 16

⇒ x – y = 3/2 ---- (2)

Adding (1) and (2)

⇒ 2x = 21/4

⇒ x = 21/8

Thus, 21/8 – y = 3/2

⇒ y = 9/8