Reena has pens and pencils which together are 40 in number. If she has 5 more pencils and 5 less pens, then number of pencils would become 4 times the number of pens. Find the original number of pens and pencils.
Let the number of pens be ‘a’ and number of pencils be ‘b’.
Given, Reena has pens and pencils which together are 40 in number. If she has 5 more pencils and 5 less pens, then number of pencils would become 4 times the number of pens.
⇒ a + b = 40 ------ (1)
Also, b + 5 = 4(a – 5)
⇒ b = 4a – 25 ------- (2)
Subtracting eq2 from eq1
⇒ a + b – b = 40 – 4a + 25
⇒ 5a = 65
⇒ a = 13