Ten years later, A will be twice as old as B and five years ago, A was three times as old as B. What are the present ages of A and B?
Let the present ages of A and B be ‘a’ and ‘b’ respectively.
Given, ten years later, A will be twice as old as B and five years ago, A was three times as old as B
⇒ a + 10 = 2(b + 10)
⇒ a = 2b + 10 ------- (1)
Also, a – 5 = 3(b – 5)
⇒ a = 3b – 10 -------- (2)
Equating eq2 and eq1
⇒ 2b + 10 = 3b – 10
⇒ b = 20
Thus, a = 2b + 10 = 50