Simplify each of the following and write as rational number of the form
:
(i) ![]()
(ii) ![]()
(iii) ![]()
(iv) ![]()
(v) ![]()
(vi) ![]()
(i) We have,
+
+ (
)
=
+
- ![]()
=
+
+ ![]()
Therefore,
L.C.M of 4, 6 and 8 is 24
= ![]()
= ![]()
(ii) We have,
+
+ (
)
=
-
- ![]()
=
+
-![]()
Therefore,
L.C.M of 3, 6 and 9 is 18
= ![]()
= ![]()
(iii) We have,
+
+ (
)
=
-
- ![]()
=
-
-![]()
Therefore,
L.C.M of 6, 2 and 8 is 24
= ![]()
= ![]()
(iv) We have,
+
+ (
)
=
-
- ![]()
=
-
-![]()
Therefore,
L.C.M of 5, 10 and 15 is 30
= ![]()
= ![]()
(v) We have,
+
+ (
)
=
-
- ![]()
=
-
-![]()
Therefore,
L.C.M of 15, 10 and 20 is 60
= ![]()
= ![]()
= ![]()
(vi) We have,
+
+ (
) + 3
=
-
-
+ 3
=
-
-
+ ![]()
Therefore,
L.C.M of 3, 2, 3 and 1 is 6
= ![]()
= ![]()