Find the product of the following binomials:
(i) (2x + y) (2x + y)
(ii) (a + 2b) (a – 2b)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
(i) (2x + y) (2x + y)
2x (2x + y) + y (2x + y)
= 4x2 + 2xy + 2xy + 3y
= 4x2 + 4xy + 3y
(ii) (a + 2b) (a – 2b)
a (a – 2b) + 2b (a – 2b)
= a2 – 2ab + 2ab – 4b2
= a2 – 4b2
a2 (a2 – bc) + bc (a2 – bc)
= a4 – a2bc + bca2 – b2c2
= a4 – b2c2
(
+
) -
(
+
)
= x2 +
yx -
–
= x2 -
y2
2x (2x - ) +
(2x -
)
= 4x2 - +
-
= 4x2 –
2a3 (2a3 – b3) + b3 (2a3 – b3)
= 4a6 – 2a3b3 + 2a3b3 – b6
= 4a6 – b6
x4 (x4 - ) +
(x4 -
)
= x8 – 2x2 + 2x2 -
= (x8 - )
x3 (x3 - ) +
(x3 -
)
= x6 – 1 + 1 -
= x6 -