The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m^{2} is Rs. 4.

Area of rhombus =

Area of rhombus =

Area of rhombus = 675 cm^{2}

Area of one tile = 675 cm^{2}

Area of 3000 tiles = 675× 3000 = 2025000 cm^{2}

Area of toles in m^{2} =

**Cost of tiles = 202.5× 4 = Rs 810.0**

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