The length of a side of a square field is 4 m. What will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonal is 2 m?
Length of square = 4 m
Area of square = side2
Area of square = 4 × 4 = 16 m2
Area of square = area of rhombus
Area of rhombus = 16 m2
Area of rhombus = 
16 = 
Other diagonal of rhombus = 16 m
In ΔAOB
Using pythagorous theorem:
AB2 = OA2 + OB2
AB2 = 82 + 12
AB2 = 65
AB = 
Rhombus is a parallelogram, area of parallelogram = base× altitude
Area of parallelogram = AB × DE
Area of parallelogram = 
× DE
DE = 
Altitude of Rhombus = 
cm
15