Find the area of the following regular hexagon.

NQ = 23 cm given

ND + QC = 23 -13 = 10

ND = QC = 5 cm

OM = 24 cm

Area of given hexagon = 2 times area of triangle MNO + area of rectangle MOPR

Area of right angled triangle =

Area of rectangle = length × breadth

Area of regular hexagon =

Area of given hexagon = = 432 cm^{2}

Therefore area of given hexagon is 432 cm^{2}

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