In a certain A.P. the 24th term is twice the 10th term. Prove that the 72nd term is twice the 34th term.
Given: a24 = 2a10
To Prove: a72 = 2a34
Proof: a24 = 2a10
a + (24 –1)d = 2a + 2(10 –1)d
23d – 18d = a
a = 5d
LHS= a72 =a + 71d =5d +71d =76d
RHS= a34 =2a + 2(33)d =10d + 66d =76d
Since, LHS=RHS
Hence, proved