Write the expressionfor the A.P.

Hence, find the common difference of the A.P. for which


(i)11th terms is 5 and 13th term is 79.


(ii)


(iii) 20th term is 10 more than the 18th term.


Let nth term an = a + (n – 1) d

= a + nd – d


kth term, ak = a + (k – 1) d


= a + kd – d


Now,


an - ak = (a + nd – d) – (a + kd – d)


= nd – kd = d (n – k)


(i) a11 = 5


a + 10d = 5 (i)


a13 = 79


a + 12d = 79 (ii)


By subtracting (i) from (ii), we get


2d = 74


d = 37


Hence, the common difference is 37


(ii)a10 = a + 9d (i)


a5 = a + 4d (ii)


a10 – a5 = a + 9d – a – 4d


200 = 5d


d = 40


Hence, common difference is 40


(iii) a20 = a + 19d (i)


a18 = a + 17d (ii)


Given that a20 = a18 + 10


a + 19d = a + 17d + 10


2d = 10


d = 5


Hence, common difference is 5


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