Write the expressionfor the A.P.
Hence, find the common difference of the A.P. for which
(i)11th terms is 5 and 13th term is 79.
(ii)
(iii) 20th term is 10 more than the 18th term.
Let nth term an = a + (n – 1) d
= a + nd – d
kth term, ak = a + (k – 1) d
= a + kd – d
Now,
an - ak = (a + nd – d) – (a + kd – d)
= nd – kd = d (n – k)
(i) a11 = 5
a + 10d = 5 (i)
a13 = 79
a + 12d = 79 (ii)
By subtracting (i) from (ii), we get
2d = 74
d = 37
Hence, the common difference is 37
(ii)a10 = a + 9d (i)
a5 = a + 4d (ii)
a10 – a5 = a + 9d – a – 4d
200 = 5d
d = 40
Hence, common difference is 40
(iii) a20 = a + 19d (i)
a18 = a + 17d (ii)
Given that a20 = a18 + 10
a + 19d = a + 17d + 10
2d = 10
d = 5
Hence, common difference is 5