If the seventh term of an A.P. is 1/9 and its ninth term is1/7, find its (63)^rd term.

a₇=

a +6d= (i)

a₉ =

a +8d= (ii)

subtracting (i) from (ii), we get,

2d=

d=

a= –

=

a₆₃= a + 62d

= +

=1