In an A.P., the sum of first n terms is . Find its 25th term.
Given, Sn=
Let an be the nth term of the A.P.
an= Sn – Sn – 1
= 3n2/2 + 13n/2 – 3(n – 1)2/2 – 13(n – 1)/2
= {n2 – (n – 1)2} +
{n – (n – 1)}
= 3n - +
= 3n + = 3n + 5
Put n = 25
a25= 3(25) + 5
= 75 + 5 = 80
Therefore, 25th term is a25 = 80