In an A.P., the first term is 2, the last term is 29 and the sum of the terms is 155. Find the common difference of the A.P.

Given, First term, a = 2

Last term, a_n = l = 29

And, Sum of terms, S_n = [a + l]

155 = [2 + 29]

155 * 2 = n * 31

n = = = 10

We know, a_n = a + (n – 1) d

29 = 2 = (10 -1) d

29 – 2 = 9d

27 = 9d

d = 3

Hence, common difference, d = 3