Construct a 
in which AB = 5 cm. 
altitude CD = 3 cm. Construct a 
similar to 
such that side of 
is 1.5 times that of the corresponding sides of 
.
Steps of construction
1. Construct a line segment AB of length 5 cm
2. From B constract an angle of 60o using compass and name it ABX
3. Construct a line EF parallel to line segment Ab at a height of 3 cm at a height of 3 cmsuch that it intersect BX at point C .Join AC
4. Construct CO perpendicular to AB . Cd is the altitude of the triangle ABC of height 3 cm
5. Construct AL making an acute angle with AB, on the side opposite to vertex C and mark 3 points(corresponding to the greater of 2 or 3) X1,X2 and X3 on AL Such that AX1=X1X2=X2X3
6. Join X2B and construct the line passing through X1 and parallel to X2B.Let this line intersect the extended line AB at R.
7.Now construct a line passing through R and parallel to BC which intersect the extended line AC at point Q
