On the same side of a tower, two objects are located. When observed from the top of the tower, their angles of depression are 45° and 60°. If the height of the tower is 150 m, find the distance between the objects.
Let the distance between the objects = (m.)
In ∆ABC,
tan 45° =
1 = ⇒
1 =
= 150 ----------(1)
In ∆ABD,
tan 60° =
√3 =
= 150
=
-------(2)
substituting value of y in eqn.(1)
=
=
⇒
⇒
=
= 63.4 m.
Therefore the distance between the points is 63.4 m.