On the same side of a tower, two objects are located. When observed from the top of the tower, their angles of depression are 45° and 60°. If the height of the tower is 150 m, find the distance between the objects.


Let the distance between the objects = (m.)


In ∆ABC,


tan 45° =


1 =


1 =


= 150 ----------(1)


In ∆ABD,


tan 60° =


√3 =


= 150


= -------(2)



substituting value of y in eqn.(1)



=


=


=


= 63.4 m.


Therefore the distance between the points is 63.4 m.


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