On the same side of a tower, two objects are located. When observed from the top of the tower, their angles of depression are 45° and 60°. If the height of the tower is 150 m, find the distance between the objects.
Let the distance between the objects =
(m.)
In ∆ABC,
tan 45° = ![]()
1 =
⇒
1 = ![]()
= 150 ----------(1)
In ∆ABD,
tan 60° = ![]()
√3 = ![]()
= 150
=
-------(2)

substituting value of y in eqn.(1)
![]()
= ![]()
=
⇒
⇒ ![]()
= ![]()
= 63.4 m.
Therefore the distance between the points is 63.4 m.