A statue 1.6 m tall stands on the top of pedestal. From a point on the ground, the angle of elevation of the top of the statue is 60° and from the same point the angle of elevation of the top of the pedestal is 45°. Find the height of the pedestal.
Let AD is statue of height 1.6 m. and BD is pedestal of height h (m).
Let the distance between point of elevation and foot of pedestal is
(m).
In ∆DBC,
tan 45° = ![]()
1 = ![]()
h =
----------(1)
In ∆ABC,
tan 60° = ![]()
√3 = ![]()
√3 = ![]()
√3
= 1.6+h -----------(2)

On substituting value of
from eqn. (1) in eqn. (2)
√3h = 1.6+h
√3h – h = 1.6
h = ![]()
on rationalizing we get.
h =
⇒
⇒ ![]()
=
=
m.
Therefore height of pedestal is
m.