A tree breaks due to the storm and the broken part bends so that the top of the tree touches the ground making an angle of 30° with the ground. The distance from the foot of the tree to the point where the top touches the ground is 10 metres. Find the height of the tree.

In fig.BD is the height of the tree. Let the broken part touches the ground at point C

BD = AB+AD

in ∆ABC

tan 30° =

=

√3h = 10

h =

h = m. -------(1)

Again ∆ABC.

COS 30° =

√3

=

= ------(2)

Therefore height of tree = () m.

Adding eqn. (1) and (2) we get,

+

= ⇒ 10√3

10× 1.732 ⇒ 17.32 m.

Therefore height of tree is 17.32 m.