A carpenter makes stools for electricians with a square top of side 0.5 m and at a height of 1.5 m above the ground. Also, each leg is inclined at an angle of 60° to the ground. Find the length of each leg and also the lengths of two steps to be put at equal distances.
In the fig let the height of the stool from the ground is 1.5m i.e. AL = BM = 1.5m
In ∆ACL
tan 60° =
√3 =
CL = ⇒
⇒ = 0.866m
Again in ∆ACL
Sin 60° =
=
AC = = √3m ⇒ 1.732m
Lengths of steps are GH and EF and steps are put at equal distance such that AP =PR = RL
Now consider ∆AGP and ∆ACL
=
=
GP = 0.2887m
Length of step = GH = GP + PQ + QH = GP + AB + GP (Since QH = GP)
GH = 2GP + AB = 2 × 0.2887 + 0.5 = 1.0774m
Similarly we can say that,
ER = ⇒
= 0.577m
Length of the step is EF = ER + RS + SF
⇒ ER + AB + ER = 2ER + AB
EF = 2× 0.5773 + 0.5 ⇒ 1.6546m