A solid iron pole having cylindrical portion 110 cm high and of base diameter 12 cm is surmounted by a cone 9 cm high. Find the mass of the pole, given that the mass of 1 cm3 of iron is 8 gm.
Given radius of cylindrical part(r)= 12/2= 6 cm
Height of cylinder (h) = 110 cm
Length of cone (l)= 9 cm
Volume of cylinder=h
V1= π (6)2 110
Volume of cone=
V2=
=108π cm3
Volume of pole =v1 + v2
=+108
= 12785.14 108 cm3
Given mass of 1cm3 of iron = 8 gm
Mass of 1275.14 cm3 of iron = 12785.14 × 8
= 102281.12
=102.2 kg
∴ Mass of pole for 12785.14 cm3 of iron is 102.2 kg