If ABCD is a rectangle with ∠BAC=32°, find the measure of ∠DBC.
Given,
ABCD is a rectangle
∠BAC = 32°
∵ we know that diagonals of a rectangle bisects each other
Hence , AO = BO
And, ∠DBA = ∠BAC = 32° (angles infront of same sides)
∵ ∠DBC+∠DBA = 90°
∴ ∠DBC = 90° - 32° = 58°