In a parallelogram ABCD, if ∠DAB=75° and ∠DBC=60°, then ∠BDC=
Given ,
In parallelogram ABCD,
∠DAB = 75°
∠DBC = 60°
∵ ∠DAB= ∠BCD [opposite angles of parallelogram]
∠BCD = 75°
Now in ∆BDC
= ∠DBC+∠BDC+∠BCD = 180°
= 60°+∠BDC+75° = 180°
=∠BDC = 180° - 135°
=∠BDC = 45°.