ABCD is a parallelogram and E is the mid point of BC.DE and AB when produced meet at F. Then, AF=
Given,
ABCD is a parallelogram
E is mid point of BC
DE & AB after producing meet at F
In ∆ECD & ∆BEF ,
∠BEF = ∠CED [vertically opposite angles]
BE = EC
∠EDC = ∠EFB [ alternate angles]
∴ ∆ECD ≅ ∆BEF
So, CD= BF
∵ AB=CD
Thus, AF= AB+ BF
= AF = AB + CD
= AF = AB+AB
= AF = 2AB