In Fig. 15.104, find the area of ΔGEF.

Given that,
ABCD is rectangle
CD = 6 cm
AD = 8 cm
We know that,
If a rectangle and a parallelogram are on the same base and between the same parallels, then the area of a triangle is equal to the half of parallelogram
So, triangle GEF and parallelogram ABCD are on the same base and between same parallels, then we know
Area of parallelogram = Base * Height
Now,
Area ( =
 =  * Area of ABCD
 * Area of ABCD
=  * AB * AD
 * AB * AD
=  * 6 * 8
 * 6 * 8
= 24 cm2
Hence,
Area ( is 24 cm2
 is 24 cm2